At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Experience the ease of finding reliable answers to your questions from a vast community of knowledgeable experts. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
Answer:
9.39 m/s
Explanation:
Using the y-direction, we can solve for the time t it takes for the cart to reach the ground.
Assume the up direction is positive and the down direction is negative.
- v₀ = 0 m/s
- a = -9.8 m/s²
- Δy = -50 m
- t = ?
Find the constant acceleration equation that contains these four variables.
- Δy = v₀t + 1/2at²
Substitute known values into this equation.
- -50 = (0)t + 1/2(-9.8)t²
Multiply and simplify.
- -50 = -4.9t²
Divide both sides of the equation by -4.9.
- 10.20408163 = t²
Square root both sides of the equation.
- t = 3.194382825
Now we can use this time t and solve for v₀ in the x-direction. Time is most often our link between vertical and horizontal components of projectile motion.
List out known variables in the x-direction.
- v₀ = ?
- t = 3.194382825 s
- a = 0 m/s²
- Δx = 30 m
Find the constant acceleration equation that contains these four variables.
- Δx = v₀t + 1/2at²
Substitute known values into the equation.
- 30 = (v₀ · 3.194382825) + 1/2(0)(3.194382825)²
Multiply and simplify.
- 30 = v₀ · 3.194382825
Divide both sides of the equation by 3.194382825.
- v₀ = 9.391485505
The cart was rolling at a velocity of 9.39 m/s (initial velocity) when it left the ledge.
Answer:
9.39 m/s
Explanation:
Using the y-direction, we can solve for the time t it takes for the cart to reach the ground.
Assume the up direction is positive and the down direction is negative.
v₀ = 0 m/s
a = -9.8 m/s²
Δy = -50 m
t = ?
Find the constant acceleration equation that contains these four variables.
Δy = v₀t + 1/2at²
Substitute known values into this equation.
-50 = (0)t + 1/2(-9.8)t²
Multiply and simplify.
-50 = -4.9t²
Divide both sides of the equation by -4.9.
10.20408163 = t²
Square root both sides of the equation.
t = 3.194382825
Now we can use this time t and solve for v₀ in the x-direction. Time is most often our link between vertical and horizontal components of projectile motion.
List out known variables in the x-direction.
v₀ = ?
t = 3.194382825 s
a = 0 m/s²
Δx = 30 m
Find the constant acceleration equation that contains these four variables.
Δx = v₀t + 1/2at²
Substitute known values into the equation.
30 = (v₀ · 3.194382825) + 1/2(0)(3.194382825)²
Multiply and simplify.
30 = v₀ · 3.194382825
Divide both sides of the equation by 3.194382825.
v₀ = 9.391485505
The cart was rolling at a velocity of 9.39 m/s (initial velocity) when it left the ledge.
We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.