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In ΔABC, a = 660 cm, b = 680 cm and c=100 cm. Find the measure of ∠B to the nearest degree.

Sagot :

olayemiolakunle65

Answer:

m∠B = [tex]97^{o}[/tex].

Step-by-step explanation:

Since the three sides of the triangle are given, then we apply cosine rule.

[tex]b^{2}[/tex] = [tex]a^{2}[/tex] + [tex]c^{2}[/tex] - 2ac Cos B

But, a = 660 cm, b = 680 cm, and c = 100 cm.

So that;

[tex]680^{2}[/tex] = [tex]660^{2}[/tex] + [tex]100^{2}[/tex] -2(660 x 100) Cos B

462400 = 435600 + 10000 - 132000 Cos B

462400 = 445600 - 132000 Cos B

132000 Cos B = 445600 - 462400

                        = -16800

Cos B = [tex]\frac{-16800}{132000}[/tex]

         = -0.1273

B = [tex]Cos^{-1}[/tex] -0.1273

  = [tex]97^{o}[/tex]

Thus, measure of ∠B is [tex]97^{o}[/tex].

sb345042716

Answer:

M∠B = 97 degrees

Step-by-step explanation:

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