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could someone please help me

Could Someone Please Help Me class=

Sagot :

Answer:

[tex] \huge \: x = 7 {0}^{o} \\ \: \huge \: y = 3 {0}^{o} \\ \huge z = {20}^{o} [/tex]

Step-by-step explanation:

to understand this

you need to know about:

  • triangles
  • equation
  • PEMDAS

tips and formulas:

  • a straight line contains 180°
  • a triangle contains 180°

let's solve:

equation for x

according to the question

110°+x=180°

x=180°-110°

x=70°

equation for y

according to the question

[tex]11 {0}^{o} + {40}^{o} + y = 18 {0}^{o} [/tex]

[tex]15 {0}^{o} + y = 180^{o} [/tex]

[tex]y = 18 {0}^{o} - 15 {0}^{o} [/tex]

[tex]y = 3 {0}^{o} [/tex]

equation for z

according to the question

90°+x+z=180°

90°+70°+z=180° (since x=70°)

160°+z=180°

z=180°-160°

z=20°

Answer:

X= 70

Z= 20

y= 30°

Step-by-step explanation:

Finding X:

Sum of angle in a straight line is 180

Therefore X = 180-110

Finding z:

Sum of angle in triangle is 180, and it’s a right angled triangle (90°)

Z= 180-(x+90)

Z= 180-( 70+90)

Finding y, look at the big triangle ABC:

There’s a right angle and <C is 40°,

Therefore <B is 180-(40+90)= 50°

<B= y + z

50° = 20° + y

y= 30°

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