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Given: <B and <D are right angles;C is the midpoint of BD.

Prove:ΔABC =ΔEDC​

Given LtB And LtD Are Right AnglesC Is The Midpoint Of BDProveΔABC ΔEDC class=

Sagot :

TheAnimeGirl

Step-by-step explanation:

Statements Reasons

In [tex] \triangle ^{s} [/tex] ABC and EDC

1.[tex] \angle \: ABC = \angle \: CDF [ A ][/tex] Both are 90° [ Given }

2. BC = CD [ S ] C is the midpoint of BD [ Given ]

3. [tex] \angle \: BAC = \angle \: CED [ A ][/tex] Alternate angles

4. [tex] \triangle ABC \cong \triangle \: EDC \: [/tex] By AAS axiom

Hence Proved !

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