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When the temperature of a reaction is raised from 278 K to 300 K, the reaction rate increases by a factor of 17. Determine the activation energy, Ea, of the reaction. R = 8.314 J/mol.K

Sagot :

Answer: The activation energy, Ea, of the reaction is 89195 Joules

Explanation:

The effect of temperature on rate constant is given by Arrhenius equation:

[tex]ln \frac{k_{2}}{k_{1}} = \frac{-E_{a}}{R}[\frac{1}{T_{2}} - \frac{1}{T_{1}}][/tex]

where  

[tex]k_2[/tex] = rate constant at temperature [tex]T_2[/tex]

[tex]k_1[/tex] = rate constant at temperature [tex]T_1[/tex]

[tex]E_a[/tex]= activation energy

R= gas constant

[tex]T[/tex] = temperature  

[tex]ln \frac{17k_1}{k_{1}} = \frac{-E_{a}}{8.314}[\frac{1}{300} - \frac{1}{278}][/tex]

[tex]2.83=\frac{-E_{a}}{8.314}[\frac{1}{300} - \frac{1}{278}][/tex]  

[tex]E_a=89195J[/tex]

The activation energy, Ea, of the reaction is 89195 Joules