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Sagot :
Hi there! Your answer to the problem would be Store A..
Step By Step Explainaction:
So we know that store A’s boxes cost $6 for each 3 boxes, and store be cost 5$ for 2 boxes.
Divide 6 with 3 since you want to know how much one would cost. 6 divide 3=6. Let check again by doing multiplication. 3x2 is also 6. This means that the cost for each box for Store A would be 2$.
Store B is the same but dividing 5$ with 2. 2x2=4 but we need to know 5. But 1 is actually .5 or 50% of 2. So it would be 2.5 or 2 and a remainder of 1. Same things...
So it would be Store A that gives cheaper cost. $2>$2.5
Given:
- Store A costs $6 for 3 boxes.
- Store B costs $5 for 2 boxes.
To find: Which store has the better deal.
Answer:
In order to do so, we'll need to divide the cost by the number of boxes to retrieve the cost of 1 box. The store with the lowest price for 1 box will have the better deal.
Let's first see what a box costs in Store A.
[tex]\sf \dfrac{Cost}{Number\ of\ boxes}\ =\ Cost\ of\ one\ box\\\\\\\dfrac{6}{3}\ =\ 2[/tex]
At Store A, the cost of a box is $2.
Now let's see what a box costs in Store B.
[tex]\sf \dfrac{Cost}{Number\ of\ boxes}\ =\ Cost\ of\ one\ box\\\\\\\dfrac{5}{2}\ =\ 2.5[/tex]
At Store B, the cost of a box is $2.5.
Since the cost at Store B seems to be a slightly higher price, Store A has the better deal.
Hope it helps. :)
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