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A person invested $150 in an account growing at a rate allowing the
money to double every 13 years. How much money would be in the
account after 22 years, to the nearest dollar?


Sagot :

Answer:y=485

y=a(2)^t/d

a=150 d=13 t=22

Step-by-step explanation: y=150(2) 22/13

y=484.759843209

y=485

The rate of the interest on the account is 5.48%. Then the amount of money after 22 years is $485.10.

What is compound interest?

Compound interest is the interest on a loan or deposit calculated based on the initial principal and the accumulated interest from the previous period.

A person invested $150 in an account growing at a rate allowing the money to double every 13 years.

Then the rate will be

[tex]\begin{aligned} 300 &= 150 (1 + r)^{13}\\\\13 \log (1 + r) &= \log 2\\\\\log (1 + r) &= 0.023156\\\\1 + r &= 1.054766\\\\r &= 0.054766 \approx 0.0548 \end{aligned}[/tex]

Then the amount of money after 22 years will be

[tex]\rm Amount = 150(1 + 0.0548)^{22}\\\\Amount = 150 \times 3.234\\\\Amount = \$ \ 485.1[/tex]

More about the compound interest link is given below.

https://brainly.com/question/25857212

#SPJ2

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