Answered

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write the equation of a circle with diameter endpoints of (-14,1) and (-10,9)

Sagot :

Yuqiao

Answer:

[tex](x+12)^2+(y-5)^2=80[/tex]

Step-by-step explanation:

First, we see that the center of the circle is (-12, 5) by taking the midpoint of the circle. Secondly, the length of diameter is [tex]\sqrt{4^2+8^2}=\sqrt{80}[/tex].

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