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Find the slope of the line that passes through(9,36) (93,-10)?

Sagot :

ameliaswan

Answer:

[tex]m = -\frac{23}{42}[/tex]

Step-by-step explanation:

here is the equation for slope (m):

[tex]m = \frac{y_2-y_1}{x_2-x_1}[/tex]

where:

y₂ = y-coordinate of 2nd point = -10

y₁ = y-coordinate of 1st point = 36

x₂ = x-coordinate of 2nd point = 93

x₁ =  x-coordinate of 1st point = 9

plug values into equation:

[tex]m =\frac{-10-36}{93-9} \\\\m = \frac{-46}{84} \\[/tex]

reduce the fraction:

[tex]m = -\frac{23}{42}[/tex]

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