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olivia's passcode has 4 digit The second digit to the left is 3 times the first (left most) digit tHe number formed by the last (right most ) 2 digits is three times the second digit to the left.the sum of the digits is 21. what is olivia's pass code

Sagot :

Answer:

3927

Step-by-step explanation:

This is the answer my teacher gave me, I promise.

The four-digit passcode is 3927 and this can be determined by using the given data and by using the hit and trial method.

Given :

  • Olivia's passcode has 4 digits.
  • The second digit to the left is 3 times the first (left most) digit.
  • The number formed by the last (right most) 2 digits is three times the second digit to the left.
  • The sum of the digits is 21.

Let the four digits passcode be 'abcd'. Then mathematical expression that represents "The second digit to the left is 3 times the first (left most) digit" is given below:

b = 3a   --- (1)

The mathematical expression that represents "the sum of the digits is 21" is given below:

a + b + c + d = 21    --- (2)

So, let a = 3, then b = 9, and the last two digits are 27. So, the number becomes 3927.

For more information, refer to the link given below:

https://brainly.com/question/25277954

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