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How many atoms are in a 121.4 gram sample of Aluminum i(Al) ?

Sagot :

Answer:

27.08 x 10²³ atoms of Al .

Explanation:

121.4 grams of Aluminum = 121.4 / 26.98  moles of Aluminum

= 4.4996 moles

1 mole of Aluminum contains 6.02 x 10²³ atoms of Al

4.4996 moles of Aluminum contains 6.02 x 10²³ x 4.4996 atoms of Al

= 27.08 x 10²³ atoms .

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