Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Join our Q&A platform to connect with experts dedicated to providing precise answers to your questions in different areas. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
Answer:
Moles of carbon atoms = 3.33 × [tex]10^{-6}[/tex] mol
No. of atoms of C in Diamond = 2.007 × [tex]10^{28}[/tex] atom
Atoms of graphite = 6.27 × [tex]10^{23}[/tex] Atoms
Explanation:
given data
Cost of 0.2g of diamond = $5000
Cost of 25 g of graphite = $ 2
solution
we know cost of 0.2g of diamond is $ 5000 so that for 1$
if buy 1$ = [tex]\frac{0.20}{5000}[/tex]
1$ = 4.0 × [tex]10^{-5}[/tex] g Carbon
and Moles of carbon atoms is express as
Moles of carbon atoms = Given mass of Carbon ÷ atomic mass of C .........1
Moles of carbon atoms = 4.0 × [tex]10^{-5}[/tex] g/ 2.0g
Moles of carbon atoms = 3.33 × [tex]10^{-6}[/tex] mol
and
No. of atoms of C in Diamond = No. of moles × Avogadro NO ..............2
No. of atoms of C in Diamond = 3.33 × [tex]10^{-6}[/tex] mol × 6.022 × [tex]10^{28}[/tex]
No. of atoms of C in Diamond = 2.007 × [tex]10^{28}[/tex] atom
Graphite
and wew have given Cost of 25 g of graphite is $2 so for but 1$ we get
for buy $1 = 25÷2 = 12.5 g Of graphite
Moles of graphite = 12.5÷12 = 1.04 mol
Atoms of graphite = 1.04 × 6.022 × 1023
Atoms of graphite = 6.27 × [tex]10^{23}[/tex] Atoms
Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.
