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Sagot :
Answer:
[tex]0.46[/tex] moles of water were removed from the sample by the heating process
Explanation:
Given
Mass of the evaporating dish [tex]= 6.488[/tex] grams
Mass of the sample of hydrate [tex]= 19.72[/tex] grams
Mass of the sample and dish after heating [tex]= 11.344[/tex] grams
The weight of water removed through evaporation
[tex]= 19.72 - 11.344 = 8.376[/tex] grams
Weight of one mole of water [tex]= 18[/tex] grams
Number of moles of water in [tex]8.376[/tex] Grams of water is equal to
[tex]\frac{8.376}{18} = 0.46[/tex] moles
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