Answer:
Following are the solution to the given points:
Step-by-step explanation:
Please find the complete question in the attached file.
In this question, we assume that "x" denotes as an actual time of the battery charging, that is a uniform random variable that [tex]x \sim U(90, 120)[/tex]
In point a:
so, pdf of x =
[tex]\to f(x)= \frac{1}{120-90} = \frac{1}{30} \\\\\to 90 < x <120[/tex]
In point b:
To find
[tex]\to P(x<110) = \int^{110}_{90} \frac{1}{30} \ dx\\\\=\frac{110-90}{30}\\\\=\frac{20}{30}\\\\=\frac{2}{3}\\\\[/tex]
In point c:
[tex]\to P(x<100) = \int^{100}_{90} \frac{1}{30} \ dx \\\\= \frac{100-90}{30}\\\\= \frac{10}{30}\\\\= \frac{1}{3}\\\\[/tex]
In point d:
[tex]\to P(95< x< 110)[/tex]
[tex]= \int^{110}_{95} \frac{1}{30} \ dx\\\\= \frac{110-95}{30} \\\\= \frac{15}{30} \\\\= \frac{1}{2}[/tex]
