Answered

Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Get quick and reliable answers to your questions from a dedicated community of professionals on our platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

A student drove to the university from her home and noted that the odometer reading of her car increased by 17.9 km. The trip took 26.6 min.
a) What was her average speed, in kilometers per hour?
b) IS she returned home by the same path 7 h 30 min after she left, what was her average speed and velocity for the entire trip?

Sagot :

abidemiokin

Answer:

See calculation below

Explanation:

Average speed = Distance/Time

a) Given

Distance = 17.9km

Time = 26.6minutes

Time = 26.6/60 hr

Time = 0.443hr

Average speed  = 17.9/0.443

Average speed = 40.38km/hr

b) If she returned home by the same path 7 h 30 min after she left, the distance will be the same;

Distance = 17.9km

Time = 7.5hr

Average speed = 17.9/7.5

Average speed = 2.387km/hr

Velocity of the entire trip = 40.38km/hr + 2.387km/hr

Velocity of the entire trip = 42.77km/hr

Hence the velocity of the entire trip is 42.77km/hr

Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.