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If Bismuth-212 has a half-life of 60.5 seconds, how many grams of the sample will be left after 121 seconds?

Sagot :

CorporalB
Depends on how many grams of the sample exist.

Think of half life as the amount of time it takes to split the item in half. With that half life, divide starting the grams by 2 (for the first 60.5 seconds). Because the question is asking for 121 seconds, divide the grams you just divided by 2 again. That should get you your answer.

Hope this helps!
Eduard22sly

The mass of the sample of Bismuth-212 having a half-life of 60.5 s that will be left after 121 s is 25 g

Assumption

Let the original mass be 100 g

How to determine the number of half-lives

  • Half-life (t½) = 60.5 s
  • Time (t) = 121 s
  • Number of half-lives (n) =?

n = t / t½

n = 121 / 60.5

n = 2

How to determine the amount remaining

  • Original amount (N₀) = 100 g
  • Number of half-lives (n) = 2
  • Amount remaining (N) =?

N = N₀ / 2ⁿ

N = 100 / 2²

N = 100 / 4

N = 25 g

Learn more about half life:

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