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Sagot :
Answer:
3927
Step-by-step explanation:
How I did this was just trial and error. 1315 doesn’t work as it only adds up to 10. Lets try 2618. It still only adds up to 17. Let’s try 3927. It Works! Many get confused as they assume “The number formed by the last (right-most) two digits is three times the second digit from the left.” As adding up the last two digits. However, getting 21 is not possible considering the circumstances If you add the last two digits as a multiple. If you have 1234, the 3” and 4” aren’t separate numbers. The 3” and 4” is 34” not 3+4.
3+9=12. 12+2=14. 14+7=21.
Using the hit and trial method and the given condition Olivia's passcode can be determined. Olivia's passcode is 3927.
Given :
Olivia has four digits passcode.
The following steps can be used in order to determine Olivia’s passcode:
Step 1 - Let Olivia's passcode be 'wxyz'.
Step 2 - The sum of all the digits is given by the equation:
w + x + y + z = 21
Step 3 - The linear equation that represents the situation "The second digit from the left is three times the first (left-most) digit" is given by:
x = 3w
Step 4 - Now, use the hit and trial method first put (w = 1) and check all the given conditions. If w = 1 then x = 3 and but the third condition that is the last (right-most) two digits is three times the second digit from the left is not satisfied.
Step 5 - Now, put (w = 3) and check all the given conditions. If w = 3 then x = 9 and the last two digits become 2 and 7. And the sum of all the digits is equal to 21.
Step 6 - From the above steps, it can be concluded that the passcode is 3927.
For more information, refer to the link given below:
https://brainly.com/question/25277954
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