Answer:
13g of CO₂ is the maximum amount that could be produced
Explanation:
The reaction of hexane with oxygen is:
C₆H₁₄ + 19/2O₂ → 6CO₂ + 7H₂O
Where 19/2 moles of oxygen react per mole of C₆H₁₄
To solve this question we need to find theoretical yield finding limiting reactant :
Moles C₆H₁₄:
4.3g C₆H₁₄ * (1mol / 86.18g) = 0.0499 moles
Moles O₂:
25.8g * (1mol / 32g) = 0.806 moles
For a complete reaction of 0.0499 moles of C₆H₁₄ are needed:
0.0499 moles of C₆H₁₄ * (19/2 mol O₂ / 1mol C₆H₁₄) = 0.474 moles of O₂.
As there are 0.806 moles, O₂ is in excess and C₆H₁₄ is limiting reactant
In theoretical yield, the moles of hexane added = 6Moles of CO₂ produced. Moles of CO₂ are:
0.0499 moles C₆H₁₄ * (6mol CO₂ / 1mol C₆H₁₄) = 0.299 moles CO₂
In grams:
0.299 moles CO₂ * (44.01g / mol) = 13g CO₂
