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Eric drops a 3.70 kg water balloon that falls a distance of 20.38 m off the top of a building. What is the velocity at the bottom?

Sagot :

onyebuchinnaji

Answer:

The velocity of the balloon at the bottom is 19.99 m/s.

Explanation:

Given;

mass of water balloon, m = 3.7 kg

height of fall, h = 20.38 m

The velocity of the balloon at the bottom is calculated from the law of conservation of energy;

[tex]K.E_{bottom} = P.E _{top}[/tex]

[tex]\frac{1}{2}mv^2 = mgh \\\\ v^2 = 2gh\\\\v= \sqrt{2gh} \\\\v = \sqrt{2\times 9.8 \times 20.38} \\\\v = 19.99 \ m/s[/tex]

Therefore, the velocity of the balloon at the bottom is 19.99 m/s.

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