Answered

Discover answers to your most pressing questions at Westonci.ca, the ultimate Q&A platform that connects you with expert solutions. Get quick and reliable solutions to your questions from a community of experienced experts on our platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

Aqueous hydrochloric acid HCl will react with solid sodium hydroxide NaOH to produce aqueous sodium chloride NaCl and liquid water H2O. Suppose 0.365 g of hydrochloric acid is mixed with 0.18 g of sodium hydroxide. Calculate the maximum mass of sodium chloride that could be produced by the chemical reaction. Round your answer to 2 significant digits.

Sagot :

jufsanabriasa

Answer:

0.26g of NaCl is the maximum mass that could be produced

Explanation:

Based on the reaction:

HCl + NaOH → NaCl + H₂O

Where 1 mol of HCl reacts per mol of NaOH to produce 1 mol of NaCl

To solve this question we need to find limiting reactant. The moles of limiting reactant = Moles of NaCl produced:

Moles HCl -Molar mass: 36.46g/mol-:

0.365g HCl * (1mol / 36.46g) = 0.010 moles HCl

Moles NaOH -Molar mass: 40g/mol-:

0.18g NaOH * (1mol / 40g) = 0.0045 moles NaOH

As the reaction is 1:1 and moles NaOH < moles HCl, limiting reactant is NaOH and maximum moles produced of NaCl are 0.0045 moles.

The mass of NaCl is:

Mass NaCl -Molar mass: 58.44g/mol-:

0.0045 moles * (58.44g/mol) =

0.26g of NaCl is the maximum mass that could be produced

We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.