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We form three groups 1, 2 and 3 using 8 red balls and 18 blue balls such that (a) all balls must be used; (b) each group must have at least one red ball and one blue ball; (c) there are strictly more blue balls than red balls in each of the three groups. How many different combinations are there

Sagot :

Answer:

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Step-by-step explanation:

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