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2/4th of the area was occupied by Himalayan panda, 1/6th by Giant Panda and 2/12th by Albino panda and remaining area by brown Panda. What is the brown panda's area

Sagot :

Answer:

[tex](\frac{1}{6}) ^{th}[/tex] of area

Step-by-step explanation:

Area occupied by Himalayan panda = [tex]\frac{2}{4}^{th}[/tex]  of area

Area occupied by Giant Panda = [tex]\frac{1}{6} ^{th}[/tex] of area

Area occupied by Albino panda = [tex]=\frac{2}{12} ^{th}[/tex]of area

Area occupied by brown Panda = [tex](1-\frac{2}{4}-\frac{1}{6}-\frac{2}{12}) ^{th}[/tex] of area

= [tex](\frac{12-6-2-2}{12} )^{th}[/tex] of area

= [tex](\frac{2}{12}) ^{th}[/tex]of area

= [tex](\frac{1}{6}) ^{th}[/tex] of area

yanellimoyett08

Answer: 3/8

Step-by-step explanation: 3/8 is the answer

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