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What is an equation of the line that passes through the points (4, -5) and (2, 0)?

Sagot :

Answer:

y = - [tex]\frac{5}{2}[/tex] x + 5

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (4, - 5) and (x₂, y₂ ) = (2, 0)

m = [tex]\frac{0+5}{2-4}[/tex] = [tex]\frac{5}{-2}[/tex] = - [tex]\frac{5}{2}[/tex] , then

y = - [tex]\frac{5}{2}[/tex] x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (2, 0 )

0 = - 5 + c ⇒ c = 0 + 5 = 5

y = - [tex]\frac{5}{2}[/tex] x + 5 ← equation of line