Answer:
[tex]3.029\ \text{m/s}[/tex]
Explanation:
m = Mass of pendulum = 1 kg
L = Length of pendulum = 2 m
g = Acceleration due to gravity = [tex]9.8\ \text{m/s}^2[/tex]
h = Height of the pendulum = 0.468 m
[tex]\theta[/tex] = Angle of deflection = [tex]-40^{\circ}[/tex]
[tex]\cos\theta=\dfrac{L-h}{L}\\\Rightarrow h=L-L\cos\theta\\\Rightarrow h=L(1-\cos\theta)\\\Rightarrow h=2(1-\cos(-40))=0.468\ \text{m}[/tex]
The energy balance of the pendulum is as follows
[tex]mgh=\dfrac{1}{2}mv^2\\\Rightarrow v=\sqrt{2gh}\\\Rightarrow v=\sqrt{2\times 9.8\times 0.468}\\\Rightarrow v=3.029\ \text{m/s}[/tex]
The maximum velocity of this pendulum is [tex]3.029\ \text{m/s}[/tex].
Answer:
Max velocity = 3.03 m/s
Explanation:
Mgh = ½ mv2
(1 kg)(9.8 m/s2)(0.468 m) = ½ (1 kg) v2
2 x 4.5864 = ½ v2 x 2
√V2 = √9.1728
V = 3.03 m/s
I hope this helps!
