Answered

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A 80 N force is needed to slide a 50.0 kg box across a flat surface at a constant velocity. What is the coefficient of kinetic friction between the box and the floor

Sagot :

samuelonum1

Answer:

0.16

Explanation:

Given data

Force F= 80N

Mass m= 50kg

Reaction R= Weight= mg= 50*9.81= 490.5N

We know that

F=UR

Substitute and solve of U

U=F/R

U= 80/490.5

U=0.16

Hence the coefficient of friction is 0.16

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