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A ball is kicked straight up into the air from a height of 48ft with an initial velocity of 88 ft/s. After how many seconds does the ball hit the ground? PLZzzzzz HELP ME

Sagot :

raphealnwobi

It would take 0.5 seconds for the ball to hit the ground.

Newton law

To solve this problem, we are to use one of newton equations. Let us use:

s = ut + (1/2)gt²

Where u is the initial velocity = 88 ft/s, s is the height = 48 feet and g is the acceleration due to gravity = 32 ft/s²

Hence:

48 = 88t + 0.5*32*t²

16t² + 88t - 48 = 0

t = -6 or 0.5

Since the time cannot be negative, hence t = 0.5 seconds

It would take 0.5 seconds for the ball to hit the ground.

Find out more on Newton law at: https://brainly.com/question/25545050

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