Answer:
2009
Step-by-step explanation:
The question can be interpreted as:
[tex]f(x) = -1.330x^2 + 5.149x + 5.517[/tex]
Required
Determine x when f(x) = 10.5
Substitute 10.5 for f(x) in [tex]f(x) = -1.330x^2 + 5.149x + 5.517[/tex]
[tex]10.5 = -1.330x^2 + 5.149x + 5.517[/tex]
Collect Like Terms
[tex]-1.330x^2 + 5.149x + 5.517-10.5=0[/tex]
[tex]-1.330x^2 + 5.149x -4.983=0[/tex]
Using quadratic formula
[tex]x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}[/tex]
Where
[tex]a = -1.330[/tex]
[tex]b = 5.149[/tex]
[tex]c = -4.983[/tex]
[tex]x = \frac{-5.149 \± \sqrt{5.149^2 - 4*-1.330*-4.983}}{2*-1.330}[/tex]
[tex]x = \frac{-5.149 \± \sqrt{0.002641}}{-2.660}[/tex]
[tex]x = \frac{-5.149 \± 0.0514}{-2.660}[/tex]
Split:
[tex]x = \frac{-5.149 + 0.0514}{-2.660}\ or\ x = \frac{-5.149 - 0.0514}{-2.660}[/tex]
[tex]x = \frac{-5.0976}{-2.660}\ or\ x = \frac{-5.2004}{-2.660}[/tex]
[tex]x = 1.92\ or\ x = 1.96[/tex]
Both values of x approximates to 2.
So:
[tex]x = 2[/tex]
2 years after 2007 is 2009.
Hence, the funding is about $10.5 billion in 2009
