Answered

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Suppose a loaded die has the following probability model: If this die is thrown and the top face shows an odd number, what is the probability that the die shows a 1

Sagot :

Answer:

the probability is 0.6

Step-by-step explanation:

The computation is shown below:

Let us assume the X would be the number appear on the top face

Now

= P(X = 1) ÷ P(X = 0)

= 0.3 ÷ 0.3 + 0.1 + 0.1

= 0.3 ÷ 0.5

= 0.6

hence, the probability is 0.6

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