Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
Answer:
Number of adult were on the trip = 4
Number of child were on the trip = 7
Step-by-step explanation:
Let the Number of adult were on the trip = x
Let the Number of child were on the trip = y
As given,
For lunch they paid $7.50 for each adult meal and $5 for each child meal for a total of $65.
⇒7.50x + 5y = 65 ...........(1)
Also,
For dinner the family paid $10.50 for each adult meal and $5 for each child meal for a total of $77.
⇒10.50x + 5y = 77 ...........(2)
Now,
Subtract equation (2) from equation (1) , we get
10.50x + 5y - ( 7.50x + 5y ) = 77 - 65
⇒10.50x + 5y - 7.50x - 5y = 12
⇒10.50x - 7.50x = 12
⇒3x = 12
⇒x = [tex]\frac{12}{3}[/tex] = 4
⇒x = 4
Now,
Put the value of x in equation (2) , we get
10.50(4) + 5y = 77
⇒42 + 5y = 77
⇒5y = 77 - 42
⇒5y = 35
⇒y = [tex]\frac{35}{5}[/tex] = 7
⇒y = 7
∴ we get
Number of adult were on the trip = x = 4
Number of child were on the trip = y = 7
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.
