Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Get quick and reliable solutions to your questions from a community of experienced experts on our platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.
Sagot :
Given:
The LCM of two numbers is 14 times their HCF.
The sum of LCM and HCF is 600.
One number is 280.
To find:
The other number.
Solution:
Let HCF of two numbers be x.
The LCM of two numbers is 14 times their HCF.
LCM = 14x
The sum of LCM and HCF is 600.
[tex]14x+x=600[/tex]
[tex]15x=600[/tex]
[tex]x=\dfrac{600}{15}[/tex]
[tex]x=40[/tex]
So, HCF = 40 and the LCM is
[tex]LCM=14(40)[/tex]
[tex]LCM=560[/tex]
We know that, if a and b are two numbers, then
[tex]a\times b=LCM(a,b)\times HCF(a,b)[/tex]
One number is 280.
[tex]280\times b=560\times 40[/tex]
[tex]b=\dfrac{560\times 40}{280}[/tex]
[tex]b=2\times 40[/tex]
[tex]b=80[/tex]
Therefore, the other number is 80.
Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.
