Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Experience the ease of finding reliable answers to your questions from a vast community of knowledgeable experts. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
Answer:
The extent to which he should build the whisper chamber along the minor axis is approximately;
14.5 ft
Step-by-step explanation:
The question examines the relationship between the dimensions of the focus, half the length of the minor axis and half the length of the major axis
let, 'c', represent the length of the focus from the center of the ellipse, let 'a', represent half the length of the major axis, and let 'b', represent half the length of the minor axis, we have;
a² = b² + c²
The given parameters are;
The length of the major axis, 2·a = 30 ft.
The distance of the focus from the center, c = 4 ft.
Therefore, we have;
a = 30 ft./2 = 15 ft.
a = 15 ft.
From a² = b² + c², we have;
b² = a² - c²
By plugging in the values, we have;
b² = (15 ft.)² - (4 ft.)² = 209 ft.²
b = √209 ft· ≈ 14.5 ft.
The distance from the center to the vertex of the minor axis of the elliptical whisper chamber, b ≈ 14.5 ft.
Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.