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Sagot :
For the first equation it should be 1 and 4 because 7(1)+6(4) would simplify to 7+24 which equals 31.
Then for the second equation, well... there’s multiple answers:
First would be 3 and -2 because 3(3)-10(-2) simplifies to 9+20=29.
Another one would be 23 and 4 because 3(23)-10(4) simplifies to 69-40=29.
Hopefully this helps :D
Then for the second equation, well... there’s multiple answers:
First would be 3 and -2 because 3(3)-10(-2) simplifies to 9+20=29.
Another one would be 23 and 4 because 3(23)-10(4) simplifies to 69-40=29.
Hopefully this helps :D
The first number will be [tex]\frac{11}{2}[/tex] and the second number will be [tex]-\frac{5}{4}[/tex].
Let the first number be x and the second number be y.
According to the question,
Since seven times the first number plus six times the second number equals 31. So,
[tex]7x+6y=31.......(1)[/tex]
Similarly,Three times the first number minus ten times the second number is 29.So,
[tex]3x-10y=29.......(2)[/tex]
Multiplying equation (1) by 3 and equation (2) by 7, we get
[tex]21x+18y=93[/tex]
[tex]21x-70y=203[/tex]
Now subtracting both the equations we get,
[tex]88y=-110[/tex]
[tex]y=-\dfrac{110}{88}[/tex]
[tex]y=-\dfrac{5}{4}[/tex]
putting the value of x in equation (1) we get,
[tex]7x+6\times-\dfrac{5}{4} =31[/tex]
[tex]7x-\dfrac{15}{2}=31\\[/tex]
[tex]7x=31+\dfrac{15}{2}[/tex]
[tex]7x=\dfrac{77}{2}[/tex]
[tex]x=\dfrac{11}{2}[/tex]
Hence the first number is [tex]\frac{11}{2}[/tex] and the second number is [tex]-\frac{5}{4}[/tex].
For more details on solving linear equation in two variables follow the link:
https://brainly.com/question/10270150
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