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Security A rounds every 2 minutes and 20 seconds in the gate 1. Security B rounds every 1 minute and 40 seconds in the gate 2. If they conduct rounds at the same time. After how many minutes they will rounds together again?

Sagot :

MrRoyal

Answer:

[tex]Time = 11\frac{2}{3}\ min[/tex]

Step-by-step explanation:

Given

[tex]Security\ A = 2\ mins, 20\ secs[/tex]

[tex]Security\ B = 1\ mins, 40\ secs[/tex]

Required

After how many minutes, will they round together

First, convert the given time to minutes

[tex]Security\ A = 2\ mins, 20\ secs[/tex]

[tex]Security\ A = 2\ mins+ 20\ secs[/tex]

[tex]Security\ A = 2\ mins+ \frac{20}{60}\ min[/tex]

[tex]Security\ A = 2\ mins+ \frac{1}{3}\ min[/tex]

[tex]Security\ A = 2\frac{1}{3}\ min[/tex]

[tex]Security\ B = 1\ mins, 40\ secs[/tex]

[tex]Security\ B = 1\ mins+ 40\ secs[/tex]

[tex]Security\ B = 1\ mins+ \frac{40}{60}\ min[/tex]

[tex]Security\ B = 1\frac{2}{3}\ min[/tex]

So, we have:

[tex]Security\ A = 2\frac{1}{3}\ min[/tex]

[tex]Security\ B = 1\frac{2}{3}\ min[/tex]

List out the multiples of the time of both security personnel take round.

[tex]Security\ A = 2\frac{1}{3}min,\ 4\frac{2}{3}min,\ 7min,\ 9\frac{1}{3}min,\ 11\frac{2}{3}min...[/tex]

[tex]Security\ B = 1\frac{2}{3}min,\ 3\frac{1}{3}min,\ 5min,\ 6\frac{2}{3}min,\ 8\frac{1}{3}min,\ 10min\ ,11\frac{2}{3}min,...[/tex]

In the above lists, the common time is:

[tex]Time = 11\frac{2}{3}\ min[/tex]

This implies that they go on round after [tex]11\frac{2}{3}\ min[/tex]

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