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Sagot :
Answer:
[tex]0.7[/tex] is the probability that the piston chosen from Machine 1 is satisfactory and the piston chosen from Machine 2 is unsatisfactory
Step-by-step explanation:
The two events are independent of each other.
Hence the probability of choosing satisfactory piston from Machine 1 and unsatisfactory piston from Machine 2 is equal probability of choosing satisfactory piston from Machine 1 + probability of choosing unsatisfactory piston from Machine 2
Substituting the given values we get
Probability of choosing satisfactory piston from Machine 1 and unsatisfactory piston from Machine 2 =[tex]\frac{174}{174 +116} + \frac{20}{180 +20}[/tex]
=[tex]\frac{174}{174 +116} + \frac{20}{180 +20}[/tex]
=[tex]= \frac{174}{290} + \frac{20}{200}\\= 0.6 + 0.1\\= 0.7[/tex]
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