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Rectangle ABCD has m∠BAC=4x+5and m∠ACD=5x−4. Find m∠CAD m∠CAD =

Sagot :

abidemiokin

Answer:

m∠CAD = 49degrees

Step-by-step explanation:

For a rectangle ABCD if m∠BAC=4x+5and m∠ACD=5x−4, then;

m∠BAC = m∠ACD (alternate angles)

4x+5 = 5x - 4

4x-5x  = -4-5

-x = -9

x = 9

Also

m∠BAC+m∠CAD = 90

4x+5+m∠CAD = 90

4(9)+5+m∠CAD = 90

36+5+m∠CAD = 90

41+m∠CAD = 90

m∠CAD = 90-41

m∠CAD = 49degrees

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