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A car weighing 16,170 newtons is placed on a hydraulic lift. Piston B has an area of 5,005 cm?

and piston A has an area of 65 cm². What force must be exerted on piston A to lift the car?

P = F/A where Pequals pressure, Fequals force, and A equals area

Sagot :

abidemiokin

Answer:

210N

Explanation:

According to pascal principle

Fb/Ab = Fa/Aa

Given

Fb = 16,170N

Ab = 5,005cm²

Fa = ?

Aa = 65 cm².

Fa is the force that must be exerted on piston A to lift the car

Substitute

16170/5005 = Fa/65

Cross multiply

5005Fa = 65 * 16170

5005Fa = 1,051,050

Fa = 1,051,050/5005

Fa = 210N

Hence the required force is 210N

Lanuel

The force which must be exerted on piston A to lift the car is equal to 210 Newton.

Given the following data:

  • Force on piston B = 16,170 newtons
  • Area of piston B = 5,005 [tex]cm^2[/tex]
  • Area of piston A = 65 [tex]cm^2[/tex]

To determine the force which must be exerted on piston A to lift the car:

Mathematically, the pressure acting on an area is given by the formula:

[tex]Pressure = \frac{Force}{Area}[/tex]

Since, the weight of the car remains constant, the pressure on piston A must be equal to the pressure on piston B.

Pressure A = Pressure B

Mathematically, this given by:

[tex]\frac{F_A}{A_A} = \frac{F_B}{A_B}[/tex]

Making [tex]F_A[/tex] the subject of formula, we have:

[tex]F_A =\frac{A_AF_B}{A_B}[/tex]

Substituting the given parameters into the formula, we have;

[tex]F_A = \frac{65 \times 16170}{5005} \\\\F_A = \frac{1,051,050}{5005}\\\\F_A = 210\;Newton[/tex]

Therefore, the force which must be exerted on piston A to lift the car is equal to 210 Newton.

Read more: https://brainly.com/question/22480179

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