Deeromero1313
Answered

At Westonci.ca, we make it easy to get the answers you need from a community of informed and experienced contributors. Join our Q&A platform and connect with professionals ready to provide precise answers to your questions in various areas. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

how to solve 16x2-16x+4=9 using square root property

Sagot :

naǫ
[tex]16x^2-16x+4=9 \\ (4x)^2-2 \cdot 2 \cdot 4x + 2^2=9 \\ (4x-2)^2=9 \\ \sqrt{(4x-2)^2}=\sqrt{9} \\ |4x-2|=3 \\ 4x-2=3 \ \lor \ 4x-2=-3 \\ 4x=5 \ \lor \ 4x=-1 \\ x=\frac{5}{4} \ \lor \ x=-\frac{1}{4} \\ \boxed{x \in \{ -\frac{1}{4}, \frac{5}{4} \} }[/tex]
We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.