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Sagot :
[tex]4x-2y=4 \\
8x+2y=20 \\ \\
\hbox{from the 1st equation:} \\
4x-2y=4 \\
-2y=-4x+4 \\
y=2x-2 \\ \\
\hbox{substitute 2x-2 for y in the 2nd equation:} \\
8x+2(2x-2)=20 \\
8x+4x-4=20 \\
12x=24 \\
x=2 \\ \\
y=2 \cdot 2-2 \\\
y=4-2 \\
y=2 \\ \\ \hbox{the answer:} \\
x=2 \\ y=2[/tex]
4x-2y=4
8x+2y=20
12x=24
x=24/12
x=2
sub x into 8x+2y=20
8(2)+2y=20
16+2y=20
2y=20-16
2y=4
y=4/2
y=2
solution (2,2)
check
4x-2y=4(2)-2(2)=4
8x+2y=8(2)+2(2)=16
hope this helps
8x+2y=20
12x=24
x=24/12
x=2
sub x into 8x+2y=20
8(2)+2y=20
16+2y=20
2y=20-16
2y=4
y=4/2
y=2
solution (2,2)
check
4x-2y=4(2)-2(2)=4
8x+2y=8(2)+2(2)=16
hope this helps
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