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Carl has three lengths of cable, 5/6 yard long, 1/4 yard long, and 2/3 yard long. after Carl has used 1 yard of cable, how much cable will he have left?

Sagot :

luana
[tex]\frac{5}{6}+\frac{1}{4}+\frac{2}{3}=\\\\\frac{10}{12}+\frac{3}{12}+\frac{8}{12}=\\\\\frac{21}{12}=\frac{7}{4}=1\frac{3}{4}\\\\1\frac{3}{4}-1=\frac{3}{4}\\\\He\ have\ left\ \frac{3}{4}\ yard\ of\ cable.[/tex]
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