Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Discover precise answers to your questions from a wide range of experts on our user-friendly Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
For the sum 15 + 45
Factors of 15 = 1, 3, 5, 15
Factors of 45 = 1, 3, 5, 9, 15, 45
GCF = 15
Rewriting 15 + 45 as (15 × 1) + (15 × 3), we can take 15 out as the common factor, and we will get 15(1+3) = 15 × 4 = 60
-----------------------------------------------------------------------------------------------------------
For the sum 9 + 27
Factors of 9 = 1, 3, 9
Factors of 27 = 1, 3, 9, 27
GCF = 9
Rewriting 9 + 27 as (9 × 1) + (9× 3) and taking the common factor, 9, out
We have 9(1+3) = 9 × 4 = 36
Writing 15 + 45 as a product of GCF ⇒ 15 ( 1 + 3 )
Writing 9 + 27 as a product of GCF ⇒ 3 ( 1 + 3 )
Factors of 15 = 1, 3, 5, 15
Factors of 45 = 1, 3, 5, 9, 15, 45
GCF = 15
Rewriting 15 + 45 as (15 × 1) + (15 × 3), we can take 15 out as the common factor, and we will get 15(1+3) = 15 × 4 = 60
-----------------------------------------------------------------------------------------------------------
For the sum 9 + 27
Factors of 9 = 1, 3, 9
Factors of 27 = 1, 3, 9, 27
GCF = 9
Rewriting 9 + 27 as (9 × 1) + (9× 3) and taking the common factor, 9, out
We have 9(1+3) = 9 × 4 = 36
Writing 15 + 45 as a product of GCF ⇒ 15 ( 1 + 3 )
Writing 9 + 27 as a product of GCF ⇒ 3 ( 1 + 3 )
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.