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As instructor grades exams, 30%; term paper, 20%; and final exam, 50%. A student had grades of 75,80, and 85, respectively, for exams, term paper, and final exam. Find the students final average. Use the weighted mean. Round your answer to one decimal place.


The students final average is ________?

Sagot :

Okay, so 75 counts for 30% (exams), 80 counts for 20% (term paper), and 85 counts for 50% (final exam)

So you would multiply 30% by 75, 20% by 80, and 50% by 85. That would be 22.5, 16, and 42.5. Add these numbers up, and put them over the total percentage, 100%. So you would have 81/100. The student's final average is 81%.
okpalawalter8

We have that  the students final average. Use the weighted mean. Rounded to one decimal place is

X=81.0\%

From the question we are told

As instructor grades exams, 30%; term paper, 20%; and final exam, 50%. A student had grades of 75,80, and 85, respectively, for exams, term paper, and final exam. Find the students final average. Use the weighted mean. Round your answer to one decimal place.

Generally the equation for the  final average is mathematically given as

X=\frac{\sum a*b}{\sum a}

X=\frac{0.3*75+0.2*80+(0.5*85}{1}

X=81\%

Therefore

the students final average. Use the weighted mean. Rounded to one decimal place is

X=81.0\%

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