Ziobro267
Answered

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What is the 6th root of 256? ...left in radical notation

Sagot :

olemakpadu
First of all we would break 256 into its simple factors.

2 / 256
2 / 128
2 /  64
2 /  32
2 /  16
2 /    8
2 /    4
2 /    2
        1.

Therefore   256 =  2 * 2 * 2 * 2 *2 * 2 * 2 *2

Therefore sixth root of 256 = [tex] \sqrt[6]{2*2*2*2*2*2*2*2} [/tex]

For every  six 2s we bring out one  out of the root.

= [tex] 2\sqrt[6]{2*2} [/tex]

= [tex] 2\sqrt[6]{4} [/tex]

That's our answer.

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