Ziobro267
Answered

Welcome to Westonci.ca, the place where your questions find answers from a community of knowledgeable experts. Get immediate answers to your questions from a wide network of experienced professionals on our Q&A platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

What is the 6th root of 256? ...left in radical notation

Sagot :

olemakpadu
First of all we would break 256 into its simple factors.

2 / 256
2 / 128
2 /  64
2 /  32
2 /  16
2 /    8
2 /    4
2 /    2
        1.

Therefore   256 =  2 * 2 * 2 * 2 *2 * 2 * 2 *2

Therefore sixth root of 256 = [tex] \sqrt[6]{2*2*2*2*2*2*2*2} [/tex]

For every  six 2s we bring out one  out of the root.

= [tex] 2\sqrt[6]{2*2} [/tex]

= [tex] 2\sqrt[6]{4} [/tex]

That's our answer.

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.