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Y=-3x+12
Y=3x-6
How do I solve this step by step system of substitution


Sagot :

luana
[tex] \left \{ {{y=-3x+12} \atop {y=3x-6}} \right. \\\\ Equal\ both\ equations\\\\\ -3x+12=3x-6\ \ \ | subtract\ 3x\\\\ -6x+12=-6\ \ \ | subtract\ 12\\\\ -6x=-18\ \ \ | divide\ by\ -6\\\\ x=3\\ y=3*3-6=9-6=3[/tex]