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Find three consecutive even integers such that the sum of the smallest and the largest is 36.

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Answer:

Step-by-step explanation:

The consecutive even integers are (2n-2), (2n), and (2n+2), where n is an integer.

(2n-2) + (2n+2) = 36

4n = 36

n = 9

(2n-2) = 16

(2n) = 18

(2n+2) = 20

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