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find the equation for the line that passes through the point (4,-3), and that is perpendicular to the line with the equation y= -3/4x-3​

Sagot :

Answer:

hi

Step-by-step explanation:

Answer

Slope between two given points (1,3) and (2,7) is

m=  

2−1

7−3

​  

=4

Then perpendicular slope is m  

1

​  

=  

4

−1

​  

 

The line equation with this slope is given by

y=  

4

−1

​  

x+c.......(1)

Now, the above line passes through the point (−4,−3)

⇒−3=  

4

−1

​  

×(−4)+c

⇒c=−4

Therefore required line is 4y+x+16=0 (Substitute  

′

c  

′

 in (1) and simplify)

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