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Resuelve en tu cuaderno el triangulo rectangulo cuya hipotenusa es 3cm y uno de sus angulos es de 70°

Sagot :

Answer:

Explanation:

Supongamos que tenemos un triángulo rectángulo cuya hipotenusa es de 3 cm y su ángulo es de 70 °.

Entonces; digamos que el triángulo rectángulo es un triángulo ABC;

dónde;

∠A =90°

∠B = 70°

∠C = ???

∠A + ∠B + ∠C = 180°

90° + 70° + ∠C = 180°

160° + ∠C = 180°

∠C = 180° - 160°

∠C = 20°

Usando la regla de trigonometría;

[tex]cos \theta = \dfrac{adjacent}{hypotenuse}[/tex]

[tex]Cos (70^0) = \dfrac{c}{3}[/tex]

[tex]c=0.342 *3\\[/tex]

[tex]c = 1.03\\[/tex]

Usando la regla de Pitágoras;

a²  =  b² + c²

3² = b² + 1.03²

9 = b² + 1.06

9 - 1.06 = b²

7.94 = b²

[tex]b = \sqrt{7.94}[/tex]

b = 2.82