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Sagot :
Answer:
Explanation:
Supongamos que tenemos un triángulo rectángulo cuya hipotenusa es de 3 cm y su ángulo es de 70 °.
Entonces; digamos que el triángulo rectángulo es un triángulo ABC;
dónde;
∠A =90°
∠B = 70°
∠C = ???
∴
∠A + ∠B + ∠C = 180°
90° + 70° + ∠C = 180°
160° + ∠C = 180°
∠C = 180° - 160°
∠C = 20°
Usando la regla de trigonometría;
[tex]cos \theta = \dfrac{adjacent}{hypotenuse}[/tex]
[tex]Cos (70^0) = \dfrac{c}{3}[/tex]
[tex]c=0.342 *3\\[/tex]
[tex]c = 1.03\\[/tex]
Usando la regla de Pitágoras;
a² = b² + c²
3² = b² + 1.03²
9 = b² + 1.06
9 - 1.06 = b²
7.94 = b²
[tex]b = \sqrt{7.94}[/tex]
b = 2.82
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