laurenn157
Answered

Get the answers you need at Westonci.ca, where our expert community is dedicated to providing you with accurate information. Discover detailed solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

A pitcher throws a ball with a mass of 0.15 kg at a batter with a velocity of 45 m/s towards the batter. The batter exerts a Force of 4500 N opposite the direction of the ball for a time of 0.003 s. What is the velocity of ball coming off the bat?

please if you can do the work i’ll mark you brainliest!!

Sagot :

Devarpita

Answer:

-135m/s

Explanation:

Impulse P=change in momentum

Let the final velocity be -Vf (negative sign due to opposite direction)

Average force =Impulse/Time

=m(-Vf-Vi)/t

=>0.15m.g (-Vf-45)/0.003=4500N

=>0.15 (-Vf-Vi)=13.5

=>(-Vf-Vi)=90

Given,Vi=45

=>(-Vf) =90+45

=>(-Vf)=135

=>Vf = -135m/s

Hope it helps!!!

The velocity of ball coming off the bat will be -135m/s. Negative shows the direction.

What is velocity?

The change of distance with respect to time is defined as velocity. It is a time-based component. Its unit is m/sec.

The given data in the problem is:

m ( mass) =0.15 Kg

u is the initial velocity of fall =45 m/sec

v is the final velocity= ?

From the Newton's second law of motion;

Impulse = change in momentum

[tex]\rm I= \triangle P \\\\ Ft = m(v-u) \\\\ 4500=\frac{0.15(V-45)}{0.003} \\\\ V = -135 \ m/sec[/tex]

Hence,the velocity of ball coming off the bat will be -135m/s.

To learn more about the velocity refer to the link;

https://brainly.com/question/862972

#SPJ2

Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.