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what is the amplitude of y = 3[6(x-4)] - 5

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Question: y = 3cos[6(x-4)] - 5

Answer: 3

Step-by-step explanation:

The reason for this is in order to find amplitude, it's always the number before "cos" or "sin". Also, the "[6(x-4)]" was just a distraction to throw you off

Here's a trick to find everything; amplitude, period, phase sift, etc.:

      y = A sin(B(x + C)) + D

* amplitude is A

* period is 2π/B

* phase shift is C (positive is to the left)

* vertical shift is D