junomary1
Answered

Welcome to Westonci.ca, where your questions are met with accurate answers from a community of experts and enthusiasts. Join our Q&A platform and connect with professionals ready to provide precise answers to your questions in various areas. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

help?
A 22.98 g sample of a compound contains 7.33 g of potassium, K, 6.65 g of chlorine, Cl, and oxygen, O. Calculate the empirical formula.

Insert subscripts as needed.

Empirical formula: KClO

Sagot :

sebassandin

Answer:

[tex]KClO_3[/tex]

Explanation:

Hello!

In this case, as we know the mass of the total sample, we can first compute the mass of oxygen:

[tex]m_O=22.9g-7.33g-6.65g=8.92g[/tex]

Next, we compute the moles of each element:

[tex]n_K=\frac{7.33g}{39.9g/mol}= 0.184mol\\\\n_{Cl}=\frac{6.65g}{35.45g/mol}=0.188mol \\\\n_O=\frac{8.92g}{16.00g/mol} =0.5575mol[/tex]

Now, we divide the moles by 0.184 moles, the fewest ones, to obtain:

[tex]K=\frac{0.184}{0.184}=1.0 \\\\Cl=\frac{0.187}{0.184}=1.0\\\\O=\frac{0.5575}{0.184} =3.0[/tex]

Therefore, the empirical formula is:

[tex]KClO_3[/tex]

Regards!

We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.