Answer:
Final temperature, T2 = 131895°C
Explanation:
Given the following data;
Mass = 50g
Initial temperature = 20°C
Quantity of heat = 5275J
Specific heat capacity = 0.50 J/g°C
To find the final temperature;
Heat capacity is given by the formula;
[tex] Q = mcdt[/tex]
Where;
Q represents the heat capacity or quantity of heat.
m represents the mass of an object.
c represents the specific heat capacity of water.
dt represents the change in temperature.
Making dt the subject of formula, we have;
[tex] dt = \frac {Q}{mc} [/tex]
Substituting into the equation, we have;
[tex] dt = \frac {5275}{50*0.50} [/tex]
[tex] dt = \frac {5275}{25} [/tex]
dt = 131875°C
Now, the final temperature T2 is;
But, dt = T2 - T1
T2 = dt + T1
T2 = 131875 + 20
T2 = 131895°C
The final temperature when a glass piece absorbs heat 5275 joules will be T2= 231 C
The heat capacity is defined as the amount of heat any material can absorb when the temperature is changed to unit quantity.
Given the following data;
Mass = 50g
Initial temperature = 20°C
Quantity of heat = 5275J
Specific heat capacity = 0.50 J/g°C
To find the final temperature;
Heat capacity is given by the formula;
[tex]Q= mc(T_2-T_1)[/tex]
Where;
Q = represents the heat capacity or quantity of heat.
M= represents the mass of an object.
C= represents the specific heat capacity
T1= initial temperature
T2 = Final temperature
Substituting into the equation, we have;
[tex]Q=mc(T_2-T_1)[/tex]
[tex](T_2-T_1)=\dfrac{Q}{mc}[/tex]
[tex](T_2-T_1)=\dfrac{5275}{50\times 0.50}[/tex]
[tex]T_2=211+T_1[/tex]
[tex]T_2=211+20=231 ^oc[/tex]
Thus the final temperature when a glass piece absorbs heat 5275 joules will be T2= 231 C
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